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  4. NO reacts with O2 to form NO2. When 10 g of NO2 is formed during the reaction, the mass of O2 consumed is

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Q. NO reacts with $O_2$ to form $NO_2$. When $10\,g$ of $NO_2$ is formed during the reaction, the mass of $O_2$ consumed is

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Solution:

$2 NO + \underset{32 g}{O _2} \rightarrow \underset{2 \times 46 g}{2 NO _2}$
$92 \,g NO _2$ uses $O _2=32 \, g$
$\therefore 10 \,g \, NO _2$ uses $O _2=3.48 \, g$