Question

Nitrobenzene on treatment with zinc dust and aqueous ammonium chloride gives

• A. $C _{6} H _{5} N = N - C _{6} H _{5}$
• B. $C _{6} H _{5} NH _{2}$
• C. $C _{6} H _{5} NO$
• D. $C _{6} H _{5} NHOH$

Answer 1

Answer: (D)

When nitrobenzene is reduced with a neutral reducing agent $\left( Zn\right.$ dust $+ NH _{4} Cl , Al - Hg$ couple and water), pheylhydroxylamine is formed.
$\underset{\text { Nitrobenzene }}{ C _{6} H _{5} NO _{2}}+2[ H ] \xrightarrow [+ NH _{4} Cl - H _{2} O ]{ Zn \text { dust }} \underset{\text { Nitrosobenzene }}{ C _{6} H _{5} NO }
\xrightarrow{2[ H ]} \underset {\text{Phenyl hydroxylamine}}{C _{6} H _{5} NHOH}$