Question

Nine cells, each of emf ε and internal resistance r, are connected in series to form a loop. If one cell is connected wrongly, then potential difference across this cell will be

• A. $\frac {16}{9} \epsilon$
• B. Zero
• C. $\frac {17}{9} \epsilon$
• D. $\frac {8}{9} \epsilon$

Answer 1

Answer: (A)

$i = \frac {8 \epsilon -\epsilon}{9r}=\frac {7\epsilon}{9r}$
$V = \epsilon +ir$
= $\epsilon +\frac {7\epsilon}{9} = \frac {16\epsilon }{9}$