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  4. Nine cells, each of emf ε and internal resistance r, are connected in series to form a loop. If one cell is connected wrongly, then potential difference across this cell will be

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Q. Nine cells, each of emf ε and internal resistance r, are connected in series to form a loop. If one cell is connected wrongly, then potential difference across this cell will be

Solution:

$ i = \frac {8 \epsilon -\epsilon}{9r}=\frac {7\epsilon}{9r}$
$V = \epsilon +ir$
= $\epsilon +\frac {7\epsilon}{9} = \frac {16\epsilon }{9}$