Question

$\left[\right.NiCl_{4}\left]\right.^{2 -},\left[\right.PtCl_{4}\left]\right.^{2 -}$ and $\left[\right.PdCl_{4}\left]\right.^{2 -}$ are respectively :-

• A. high spin, low spin, high spin
• B. low spin, low spin, low spin
• C. high spin, low spin, low spin
• D. low spin, high spin, high spin

Answer 1

Answer: (C)

$\left[\right.NiCl_{4}\left]\right.^{2 -} \rightarrow $ Ni is 3d series element

$ \rightarrow Cl^{-}$ weak ligand

$ \rightarrow $ High spin

$\left[\right.PdCl_{4}\left]\right.^{2 -} \rightarrow $ Pd is 4d series element

$ \rightarrow $ Low spin

$\left[\right.PtCl_{4}\left]\right.^{2 -} \rightarrow $ Pt is 5d series element

$ \rightarrow $ $\text{Cl}^{-}$ act as strong field ligand for $\text{Pt}$ and $\text{Pd}$ as they are $\text{5d,} \, \text{4d}$ elements respectively with high effective nuclear charge.