Question

$NH_{4}NO_{2} \rightarrow N_{2}+2H_{2}O$
The equivalent mass of $NH_{4}NO_{2}$ (molar mass $=M$ ) in the above reaction is:

• A. $\frac{M}{2}$
• B. $M$
• C. $\frac{M}{3}$
• D. $\frac{M}{4}$

Answer 1

Answer: (C)

$n$ -factor of $NH_{4}NO_{2}$ is $3$ .