Question

Negation of the statement $p$ : for every real number, either $x \geq$ or $x < 1$ is

• A. There exist a real number x such that neither $x > 1$ nor $x < 1$
• B. There exist a real number x such that $0 < x < 1$ .
• C. There exist a real number x such that neither $ x \geq 1 $ , nor $x \leq 1$
• D. none of these

Answer 1

Answer: (A)

Negation of given statement $p \vee q$ is $\sim (p \vee q) = \sim p \wedge \sim q \, \therefore \,$.