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  4. NaHC 2 O 4 is 0.1 M when neutralized with NaOH.Hence, it is ........ when oxidized with MnO 4- / H +

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Q. $NaHC _2 O _4$ is $0.1 \,M$ when neutralized with $NaOH$.Hence, it is ........ when oxidized with $MnO _4^{-} / H ^{+}$

Some Basic Concepts of Chemistry

Solution:

$NaHC _2 O _4 \rightleftharpoons Na ^{+}+ H ^{+}+ C _2 O _4^{2-}$
$NaOH$ neutralises $H ^{+}$
$MnO _4^{-} / H ^{+}$oxidises $C _2 O _4^{2-}$ to $CO _2$
Thus, $0.1\, M =0.2\, N$