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Q. $Na_{2}B_{4}O_{7} + X \to H_{3}BO_{3}$. What is $X$ in the reaction?

The p-Block Elements

Solution:

$Na_{2}B_{4}O_{7}+2HCl+5H_{2}O \to2NaCl+4H_{3}BO_{3}$
$Na_{2}B_{4}O_{7}+H_{2}SO_{4}+5H_{2}O\to Na_{2}SO_{4}+4H_{3}BO_{3}$