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Chemistry
N2O4(g) leftharpoons 2NO2(g); Kc=5.7 × 10-9 at 298 K At equilibrium
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Q. $N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$; $K_c=5.7 \times 10^{-9}$ at $298\,K$ At equilibrium
Equilibrium
A
concentration of $NO_2$ is higher than that of $N_2O_4$
12%
B
concentration of $N_2O_4$ is higher than that of $NO_2$
54%
C
both $N_2O_4$ and $NO_2$ have same concentration
29%
D
concentration of $N_2O_4$ and $NO_2$ keeps on changing
5%
Solution:
Smaller value of equilibrium constant $(< 10^{-3})$ signifies the greater concentration of reactants as compared to that of products.