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  4. n- propyl bromide on treating with alcoholic KOH produce

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Q. $n-$ propyl bromide on treating with alcoholic $KOH$ produce

KCETKCET 2008Hydrocarbons

Solution:

Alcoholic $KOH$ is a dehydrohalogenating reagent, so when n-propyl bromide is treated with alcoholic $KOH$, propene is obtained.

$ \underset{\text{n - propyl bromide }}{CH_3CH_2CH_2Br + alc\;KOH} \longrightarrow \underset{\text{propene }}{CH_3CH =CH_2 +HBr } $