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Q. $n$ cells each of emf $\varepsilon$ and internal resistance $r$ send the same current through an external resistance $R$ whether the cells are connected in series or in parallel. Then

Current Electricity

Solution:

Cells in series,
Current through the external resistance,
$I=\frac{n \varepsilon}{R+n r}$
Cells in parallel, $I=\frac{\varepsilon}{R+\frac{r}{n}}=\frac{n \varepsilon}{n R+ r}$
According to problem, $\frac{n \varepsilon}{R+n r}=\frac{n \varepsilon}{n R+ r}$
or, $R+n r=n R +r \Rightarrow R(1-n)=r(1-n)$
$\Rightarrow R=r$