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  4. n balls each of mass m impinge elastically each second on a surface with velocity u. The average force experienced by the surface will be

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Q. $n$ balls each of mass $m$ impinge elastically each second on a surface with velocity $u$. The average force experienced by the surface will be

Laws of Motion

Solution:

Change in momentum of one ball $=2 m u$, time taken $=1 s$
$F_{ av }=\frac{\text { Total change in momentum }}{\text { Time taken }}$
$=\frac{n(2 m u)}{1}=2\, m n u$