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Q. Motion of a particle is given by equation $s = (3t^3+7t^2+14t+8)\, m.$ The value of acceleration of the particle at $t = 1\ sec$ is

AIPMTAIPMT 2000Motion in a Straight Line

Solution:

$\, \, \, \frac{ds}{dt}=9t^2+14t+14$
$\Rightarrow \frac{d^2s}{dt^2}=18t+14=a$
$ \, \, \, a_{t=1} = 18 \times 1 + 1 4 = 32\, m/s^2$