Question

Element "$E$" belongs to the period $4$ and group $16$ of the periodic table. The valence shell electron configuration of the element, which is just above ‘$E$’ in the group is

• A. $3 s^{2} \cdot 3 p^{4}$
• B. $3 d ^{10} \cdot 4 s ^{2} \cdot 4 p ^{4}$
• C. $4 d ^{10} \cdot 5 s ^{2}, 5 p ^{4}$
• D. $2 s ^{2}, p 4$

Answer 1

Answer: (A)

$E \Rightarrow[ Ar ] 3 d ^{10} 4 s ^{2} 4 p ^{4}$
Element above $E \Rightarrow[ Ne ] 3 s ^{2} 3 p ^{4}$