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  4. Moment of inertia of circular loop of radius R about the axis of rotation parallel to horizontal diameter at a distance R/2 from it is

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Q. Moment of inertia of circular loop of radius R about the axis of rotation parallel to horizontal diameter at a distance R/2 from it is

System of Particles and Rotational Motion

Solution:

Applying theorem of parallel axis
$I=I_{CM}+M\left(\frac{R}{2}\right)^2$
$I=\frac{1}{2}MR^2+\frac{MR^2}{4}$
$I=\frac{3}{4}MR^2$