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Q. Moment of inertia of a ring of mass m = 3 gm and radius r = 1 cm about an axis passing through its edge and parallel to its natural axis is:

JIPMERJIPMER 2000

Solution:

Applying theorem of parallel axis $ I=2m{{R}^{2}} $ $ I=2\times 3\times {{(1)}^{2}}=6gm\,\,c{{m}^{2}} $