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  4. Moment of inertia of a disc of mass M and radius ' R ' about any of its diameter is (M2/4). The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, (x/2) MR 2. The value of x is

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Q. Moment of inertia of a disc of mass $M$ and radius ' $R$ ' about any of its diameter is $\frac{M^2}{4}$. The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, $\frac{x}{2} MR ^2$. The value of $x$ is __

JEE MainJEE Main 2023System of Particles and Rotational Motion

Solution:

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$ I = I _{ cm }+ Md ^2 $
$ =\frac{ MR ^2}{2}+ MR ^2 $
$ =\frac{3}{2} MR ^2 $
$ x =3$