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Q.
Mole ratio of $Fe$ in $FeO , Fe _{2} O _{3}$ and $Fe _{3} O _{4}$ samples of equal weights is
NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry
Solution:
As mole, $n=\frac{w}{\text { molecularwt. }}$
Moles of $FeO : Fe _{2} O _{3}: Fe _{3} O _{4}$
$\frac{w}{72}: \frac{w}{160}: \frac{w}{232}$
moles of $F e=\frac{w}{72}: \frac{2 \times w}{160}: \frac{3 w}{232}$
i.e., $1: 0.9: 0.93 .$