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Q. Mole fraction of ethyl alcohol in aqueous ethyl alcohol solution is $0.25$. Hence percentage of ethyl alcohol by weight is

Some Basic Concepts of Chemistry

Solution:

Mole fraction of $H_2O = 1 - 0.25 = 0.75$
$\frac{x_{C_2H_5OH}}{X_{C_2H_5OH} \,+\, X_{H_2O}} = \frac{n_{_{C_2H_5OH}}}{n_{C_2H_5OH} \,+\, n_{H_2O}}$
or wt. $\% = \frac{0.25\,\times\,46}{0.25\,\times\,46\,+\,0.75\,\times\,18}\times 100 = 46\%$.