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Q. Molar concentration of $96\, g$ of $O_{2}$ contained in a $2\, L$ vessel is:

Equilibrium

Solution:

Molar concentration
$ \frac{\text { Mumber of moles of } O _{-}\{2\}}{\text { volume (in litre) }}=\frac{96}{32} \times \frac{1}{2}=1.2 mol L $