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  4. Molality of a sulphuric acid solution in which the mole fraction of water is 0.85 is :-

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Q. Molality of a sulphuric acid solution in which the mole fraction of water is $0.85$ is :-

NTA AbhyasNTA Abhyas 2020

Solution:

$X_{H_{2} O}=0.85X_{H_{2} SO_{4}}=0.15$
$\frac{X_{H_{2} SO_{4}}}{X_{H_{2} O}}=\frac{m_{H_{2} SO_{4}}}{ m_{H_{2} O}}=\frac{0 . 15}{0 . 85}$
$m=\frac{0 . 15 \times 1000}{0 . 85 \times 18}=9.8m$