1. Tardigrade
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  3. Chemistry
  4. Molality of 1 M NaNO 3 solution (Density of solution is 1.25 g mL -1 and mol. wt. of NaNO 3=85 g mol -1 ) is

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Q. Molality of $1 M NaNO _{3}$ solution (Density of solution is $1.25 g mL ^{-1}$ and mol. wt. of $NaNO _{3}=85 g mol ^{-1}$ ) is

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Solution:

$\rho=1.25 \,g\, mL ^{-1}$,

$ M_{ NaNO _{3}}=85 \,g \,mol ^{-1}$,

Molarity $=1 \,M$

$\frac{1}{m}=\frac{\rho}{M}-\frac{M_{ NaNO ,}}{1000}$

$ \Rightarrow \frac{1}{m}=\frac{1.25}{1}-\frac{85}{1000}$

$=1.25-0.085=1.165$

$m=0.858$