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  4. Mixture X= 0.02 mole of [Co(NH3)5SO4]Br and 0.02 mole of [Co(NH3)5Br]SO4 was prepared in 2 L of solution. 1 L of mixture X + excess AgNO3 arrow Y 1 L of mixture X + excess BaCI2 arrow Z Number of moles of Y and Z are

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Q. Mixture $X= 0.02$ mole of $[Co(NH_3)_5SO_4]Br $ and $0.02$ mole of $[Co(NH_3)_5Br]SO_4 $ was prepared in $2 \,L$ of solution.
$1\, L$ of mixture $X +$ excess $AgNO_3 \rightarrow Y $
$1\, L$ of mixture $X$ + excess $BaCI_2 \rightarrow Z $
Number of moles of $Y$ and $Z$ are

IIT JEEIIT JEE 2003Coordination Compounds

Solution:

In $1 \,L$ solution, there will be $0.01$ mole of each $[Co(NH_3)_5SO_4] Br$ and $[Co(NH_3)_5Br]SO_4. $ Addition of excess of $AgNO_3 $ will give $0.01$ mole of $AgBr$. Addition of excess of $BaCl_2 $ will give $0.01$ mole of $BaSO_4. $