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  4. Mixture of two bivalent metals A and B having mass 2 g when dissolved in HCl at STP, 2.24 L H2 is evolved. What is the mass of A present in mixture? (Atomic mass of A = 15 u, B = 30 u)

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Q. Mixture of two bivalent metals $A$ and $B$ having mass $2\,g$ when dissolved in $HCl$ at STP, $2.24\, L \,H_2$ is evolved. What is the mass of A present in mixture? (Atomic mass of $A = 15 u, B = 30 u$)

AIIMSAIIMS 2018Some Basic Concepts of Chemistry

Solution:

$A +2 HCl \longrightarrow ACl _2+ H _2$
Mole $: \frac{x}{15} \frac{x}{15}$
$B +2 HCl \longrightarrow BCl _2+ H _2$
Mole $: \frac{2-x}{30} \frac{2-x}{30}$
Total moles of $H _2=\frac{x}{15}+\frac{2-x}{30}=\frac{2.24}{22.4}=\frac{1}{10}$
$\Rightarrow x=1 g$