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Q. $Mg\left(\right.s\left.\right)\left|\right.Mg^{2 +}\left(\right.aq\left.\right)\left|\right.\left|\right.Zn^{2 +}\left(\right.aq\left.\right)\left|\right.Zn\left(\right.s\left.\right);E^\circ =+3.13\text{V}$

The correct plot of $E_{c e l l}$ versus $log \frac{\left[\right. M g^{2 +} \left]\right.}{\left[\right. Z n^{2 +} \left]\right.}$ will be represented as

NTA AbhyasNTA Abhyas 2020Electrochemistry

Solution:

For the given cell,

$\text{E} \, \text{=} \, \text{E}^{\text{o}} - \frac{\text{0} \text{.059}}{\text{2}} \text{log}_{\text{10}} \frac{\left[\text{Mg}^{\text{2+}}\right]}{\left[\text{Zn}^{\text{2+}}\right]}$

This equation is of the form $\text{y} \, \text{=} \, \text{mx} \, \text{+} \, \text{c,}$ its slope is negative and intercept equal to $\text{E}^{\text{o}}$

$Slope=-\frac{0.059}{2}$

Intercept $\text{=} \, \text{E}^{\text{o}}$ .