Question

Methyl benzoate can be prepared by

• A. $C _{6} H _{5} COOH + CH _{3} OH \xrightarrow{ H ^{+}}$
• B. $C _{6} H _{5} COOCl + CH _{3} OH \xrightarrow{\text { Pyridine }}$
• C. $C _{6} H _{5} COOH + CH _{2} N _{2} \rightarrow$
• D. All of the above method

Answer 1

Answer: (D)

${C_6}{H_5}COOH + C{H_3}OH\xrightarrow{{H^+ }} \underset{\text{methyl benzoate}}{{C_6}{H_5}COOHC{H_3}} + {H_2}O$ (The reaction is methyl benzoate known as Fischer - Sprier esterification reaction.)
${C_6}{H_5}COCl + C{H_3}OH\xrightarrow{\text{Pyridine }}{C_6}{H_5}COOC{H_3} + HCl$
$C _{6} H _{5} COOH +\underset{\text { diazomethane }}{ CH _{2}} \xrightarrow{ N _{2}} C _{6} H _{5} COOCH _{3}+ N _{2}$
(Methyl easters can be prepared by treating carboxylic acid with ethereal solution of diazomethane.
Hence, methyl benzoate can be prepared by all these above methods.