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Chemistry
Methanides are
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Q. Methanides are
The s-Block Elements
A
$Mg_2C_3, Be_2C, Al_4C_3$ and $CaC_2 $
B
$Mg_2C_3, Be_2C $ and $ Al_4C_3 $
C
$Be_2C, Al_4C_3 $ and $CaC_2 $
D
$ Be_2C $ and $Al_4C_3 $
Solution:
Methanides give $CH_4$ on reaction with $H_2O$.
$Al_4C_3 + 12H_2O \rightarrow 4Al(OH)_3 + 3CH_4 $
$ Be_2C + 4H_2O \rightarrow 2Be(OH)_2 + CH_4 $