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  4. Methane reacts with excess of chlorine in diffused sunlight to give the final product as

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Q. Methane reacts with excess of chlorine in diffused sunlight to give the final product as

Hydrocarbons

Solution:

$CH_4 \xrightarrow[Cl_2]{hv}CH_3Cl \xrightarrow[-HCl]{h\nu /Cl_2} CH_3Cl_2 \xrightarrow[-HCl]{h\nu /Cl_2}$
$CHCl_3 \xrightarrow[Cl_2]{h\nu} CCl_4$