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  4. Methane + 10% O2 xrightarrow[Cu tube]200° C Product; product will be

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Q. Methane + 10% $ {{O}_{2}}\xrightarrow[Cu\,tube]{200{}^\circ C} $ Product; product will be

Rajasthan PETRajasthan PET 2002

Solution:

$ \underset{methane}{\mathop{C{{H}_{4}}}}\,+10%{{O}_{2}}\xrightarrow[Cu-tube]{200{}^\circ C}\underset{methanol}{\mathop{C{{H}_{3}}-OH}}\, $ v