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Mathematics
Mean of 10 observations is 50 and their standard deviation is 10. If each observation is subtracted by 5 and then divided by 4, then the new mean and standard deviation are
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Q. Mean of $10$ observations is $50$ and their standard deviation is $10$. If each observation is subtracted by $5$ and then divided by $4$, then the new mean and standard deviation are
KEAM
KEAM 2013
Statistics
A
22.5, 2.5
17%
B
11.25, 2.5
55%
C
11.5, 2.5
24%
D
11, 2.5
0%
E
11.75, 2.5
0%
Solution:
Given,
Mean of 10 observations $=\frac{\displaystyle\sum_{i=1}^{10} x_{i}}{10}=50$
$\Rightarrow \, \displaystyle\sum_{i=1}^{10} x_{i}=500\,\,\,\,\,\dots(i)$
$\therefore $ New mean $=\frac{\displaystyle\sum_{i=1}^{10} x_{i}-5 \times 10}{4 \times 10}=\frac{500-50}{4 \times 10}$
[using Eq. (i)]
$=\frac{450}{4 \times 10}=11.25$
and standard deviation $=\frac{\text { old }( SD )}{4}=\frac{10}{4}=2.5$