Question

Match the thermodynamic processes taking place in a system with the correct conditions. In the table : $\Delta Q$ is the heat supplied, $\Delta W$ is the work done and $\Delta U$ is change in internal energy of the system :

Process		Condition
(I)	Adiabatic	(A)	$\Delta W =0$
(II)	Isothermal	(B)	$\Delta Q =0$
(III)	Isochoric	(C)	$\Delta U \neq 0, \Delta W \neq 0$ $\Delta Q \neq 0$
(IV)	Isobaric	(D)	$\Delta U =0$

• A. $I - B , II - D , III - A , IV - C$
• B. $I - B , II - A , III - D , IV - C$
• C. $I - A , II - A , III - B , IV - C$
• D. $ I- A , II - B , III - D , IV - D $

Answer 1

Answer: (A)

(I) Adiabatic process $\Rightarrow \Delta Q=0$
No exchange of heat takes place with surroundings
(II) Isothermal proess $\Rightarrow $ Temperature remains
$\text { constant }(\Delta T =0)$
$\Delta u =\frac{ F }{2} nR \Delta T \Rightarrow \Delta u =0$
No change in internal energy $[\Delta u =0]$
(III) Isochoric process Volume remains constant
$\Delta V =0 $
$W =\int P.dV =0$
Hence work done is zero.
(IV) Isobaric process $\Rightarrow $ Pressure remains constant
$W = P . \Delta V \neq 0$
$\Delta u =\frac{ F }{2} nR \Delta T =\frac{ F }{2}[ P \Delta V ] \neq 0$
$\Delta Q=n C_{p} \Delta T \neq 0$