Q.
Match the intermediates given in Column I with their probable structures in Column II
Column I
Column II
(A)
Free radical
(i)
Trigonal planar
(B)
Carbocation
(ii)
Pyramidal
(C)
Carbanion
(iii)
Linear
Column I | Column II | ||
---|---|---|---|
(A) | Free radical | (i) | Trigonal planar |
(B) | Carbocation | (ii) | Pyramidal |
(C) | Carbanion | (iii) | Linear |
Organic Chemistry – Some Basic Principles and Techniques
Solution:
Column I
Column II
i
Free radical
Free radical is formed as a result of hemolytic fission and C becomes sp 2 hybridized. Shape of free radical is trigonal planar
ii
Carbocation
In carbocation, positively charged $C$ is $sp^2$ hybridized and shape is trigonal planar
iii
Carbonation
In carbanion, negatively charged $C$ is $sp^3$ hybridized with lone pair and shape Carbanion Is pyramidal
Column I | Column II | ||
---|---|---|---|
i | Free radical | Free radical is formed as a result of hemolytic fission and C becomes sp 2 hybridized. Shape of free radical is trigonal planar | |
ii | Carbocation | In carbocation, positively charged $C$ is $sp^2$ hybridized and shape is trigonal planar | |
iii | Carbonation | In carbanion, negatively charged $C$ is $sp^3$ hybridized with lone pair and shape Carbanion Is pyramidal |