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Q. Match the intermediates given in Column I with their probable structures in Column II
Column I Column II
(A) Free radical (i) Trigonal planar
(B) Carbocation (ii) Pyramidal
(C) Carbanion (iii) Linear

Organic Chemistry – Some Basic Principles and Techniques

Solution:

Column I Column II
i Free radical Free radical is formed as a result of hemolytic fission and C becomes sp 2 hybridized. Shape of free radical is trigonal planar
ii Carbocation In carbocation, positively charged $C$ is $sp^2$ hybridized and shape is trigonal planar
iii Carbonation In carbanion, negatively charged $C$ is $sp^3$ hybridized with lone pair and shape Carbanion Is pyramidal