Question

Match the following and choose the CORRECT combination from the options given.

	Column I (Family)		Column II (Androecium formula)
$\left(A\right)$	Brassicaceae	$1.$	$A_{3 + 3}$
$\left(B\right)$	Fabaceae	$2.$	$A_{\left(\right. 5 \left.\right)}$
$\left(C\right)$	Solanaceae	$3.$	$A_{\left(9\right) + 1}$
$\left(D\right)$	Liliaceae	$4.$	$A_{2 + 4}$

• A. A-4, B-3, C-2, D-1
• B. A-1, B-2, C-3, D-4
• C. A-2, B-3, C-4, D-1
• D. A-3, B-4, C-1, D-2

Answer 1

Answer: (A)

Floral formula is the representation of the count and arrangement of the whorls of the flower. It is unique for a particular family of flowering plants and symbols are used for representation. 'A' signifies male reproductive part androecium. Similarly, G is for gynoecium, K for calyx and P for corolla.
Androecium is the male reproductive part of the flower having stamen made of filament (stock) and the anther. Anther is the sac like structure where the male gamete containing structures, pollen grains are formed.
Fabaceae, a.k.a. Leguminosae is the family of plant having legumes, peas group in them. This group is the third largest group and economically important family of flowering plants. The male part in floral diagram is represented as $A_{9 + \, 1}$ , meaning 10 stamens are present of which 9 are fused and 1 is not-attached with anther been dithecous.
Solanaceae also called 'potato family' are found in regions of tropics, subtropics and temperate zones. Mostly have herbs and shrubs types of plants. The male reproductive part in the floral formula is A₍₅₎, where there are 5 fused stamens and they are epipetalous.
Liliaceae, the lily family, form the representative of the monocot plants. Its as six stamens arranged in sets of three without fusion.
Brassicaceae includes the mustard plant group where the 6 male parts (stamen) of flower are arranges as sets of 2 and 4 without been fused. They are diadelphous.