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Q. Match the following.
(1) Energy of ground state of $He^{+}$ (p) 6.04 eV
(2) Potential energy of 1 orbit of H atom (q) -27.2 eV
(3) Kinetic energy of II excited state of $He^{+}$ (r) 54.4 eV
(4) Ionisation potential of $He^{+}$ (s) -54.4 eV

NTA AbhyasNTA Abhyas 2022

Solution:

Energy of G.S. of $He^{+}=E_{H}\times Z^{2}$
$= - 13.6 \times 4 = - 54.4 \, \text{eV}$
Ionisation potential of $He^{+}=E_{\in fty}-E_{1}$
$= - \left(- 54.4\right) = 54.4 \, \text{eV}$
T.E. of H of 1 orbit $= - 13.6 \, \text{eV}$
2 T.E. = P.E. and $\text{K} \text{.E} = - \text{ T} \text{. E}$
$\text{P} \text{.E} \text{.} \, = - 2 \times 13.6 = - 27.2 \, \text{eV}$
T.E. of H of II excited state $=\frac{- 13.6}{9}\times 4$
of $\text{He} \, = - 6.04 \, \text{eV}$
$\text{K} \text{.E} \text{.} = - \text{(T} \text{.E} \text{.)} = - \left(- 6.04 \, \text{eV}\right) = + 6.04 \, \text{eV}$