Question

Match the elements of table I and table II.
$\quad$$\quad$Table I $\quad$$\quad$$\quad$$\quad$$\quad$$\quad$$\quad$ Table II
1.$\quad$ Myopia$\quad$$\quad$$\quad$$\quad$$\quad$ (i) $\quad$Bifocal lens
2. $\quad$Hypermetropia$\quad$$\quad$ (ii) $\quad$Cylindrical lens
3. $\quad$Presbyopia$\quad$$\quad$$\quad$$\quad$ (iii) $\quad$Concave lens
4.$\quad$ Astigmatism$\quad$$\quad$$\quad$$\quad$ (iv)$\quad$ Convex lens

• A. 1 - iii, 2 - iv, 3 - i, 4 - ii
• B. 1 - iv, 2 - iii, 3 - i, 4 - ii
• C. 1 - i, 2 - ii, 3 - iii, 4 - iv
• D. 1 - ii, 2 - iv, 3 - i, 4 - iii

Answer 1

Answer: (A)

For myopia (shortsightedness) a convex lens is used. For hypermetropia, we need concave or diverging lens for the ray of light to be focused on the retina. For presbyopia bifocal lens is used and astigmatism is cleared with cylindrical lenses. Therefore the correct alternative is (a)