Question

Match the column $I$ with column $II$ and mark the appropriate choice.

Column $I$		Column $II$
(A)	Clemmensen reduction	(i)	Conc. $KOH$
$(B)$	Rosenmund reduction	(ii)	$Zn/Hg +$ conc. $HCl $
$(C)$	Iodoform reaction	(iii)	$H_{2}/Pd-BaSO_{4}$
$(D)$	Cannizzaro reaction	(iv)	$NaOH +I_{2} $

• A. $\left(A\right) \rightarrow\left(i\right), \left(B\right) \rightarrow \left(iii\right), \left(C\right)\rightarrow \left(ii\right), \left(D\right) \rightarrow \left(iv\right) $
• B. $\left(A\right) \rightarrow\left(iii\right), \left(B\right) \rightarrow \left(iv\right), \left(C\right)\rightarrow \left(i\right), \left(D\right) \rightarrow \left(ii\right) $
• C. $\left(A\right) \rightarrow\left(ii\right), \left(B\right) \rightarrow \left(iii\right), \left(C\right)\rightarrow \left(iv\right), \left(D\right) \rightarrow \left(i\right) $
• D. $\left(A\right) \rightarrow\left(iv\right), \left(B\right) \rightarrow \left(i\right), \left(C\right)\rightarrow \left(ii\right), \left(D\right) \rightarrow \left(iii\right) $

Answer 1

Answer: (C)

Clemmensen reduction: $Zn \mid Hg +$ conc.HCl
Clemmensen reduction reduces Aldehydes and ketones to corresponding hydrocarbons.
Rosenmund reduction: $H _{2} / Pd - BaSO _{4}$
The Rosenmund reduction is used to prepare aldehyde from acyl halide.
Iodoform reaction: $I _{2}+ NaOH$
Idoform reaction used for the identification of methyl ketone.
Cannizzaro:Conc.$KOH$
Cannizzaro's reaction is a disproportionation reaction.
It is shown by the aldehydes or
ketones which do not have $\alpha$-hydrogen atoms.