Question

Match List I with List II

LIST I		LIST II
A	Isothermal Process	I	Work done by the gas decreases internal energy
B	Adiabatic Process	II	No change in internal energy
C	Isochoric Process	III	The heat absorbed goes partly to increase internal energy and partly to do work
D	Isobaric Process	IV	No work is done on or by the gas

Choose the correct answer from the options given below:

• A. A-I, B-II, C-IV, D-III
• B. A-II, B-I, C-IV, D-III
• C. A-I, B-II, C-III, D-IV
• D. A-II, B-I, C-III, D-IV

Answer 1

Answer: (B)

$\Delta U = nC _{ v } \Delta T$
For isothermal process $T$ is constant
So $\Delta U =0$
$A \longrightarrow II$
Adiabatic process
$ \Delta Q = 0 $
$ \Delta Q =\Delta U +\Delta W $
$\Delta U =-\Delta W$
Work done by gas is positive
So $\Delta U$ is negative
$\text { B } \longrightarrow \text { I }$
For Isochoric process $\Delta W =0$
$C \longrightarrow IV$
For Isobaric process
$\Delta W = P \Delta V \neq 0$
$\Delta U = nC _{ V } \Delta T \neq 0$
Heat absorbed goes partly to increase internal energy and partly do work.