Thank you for reporting, we will resolve it shortly
Q.
Mass of a block is $20\,kg$. A man of mass $60\,kg$
raises it with constant velocity as shown in the figure.
Force exerted by man on the floor will be :-
Laws of Motion
Solution:
$T=20\, kg \,w t=20 \times g N$
$F _{ Net }= W _{ m }- T =60\, g -20\, g $
$=40\, g =400\, N$