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Q. Mars has about $\frac{1}{10}$ th as much mass as the Earth and half as great a diameter. The acceleration of falling body on Mars is nearly

Gravitation

Solution:

$\dot{g}=\frac{G M}{R^{2}}$
$g_{\text {Mars }}=\frac{G(M \cap 0)}{(R / 2)^{2}}=\frac{4}{10} g=0.4 \times 9.8 ms ^{-2}=3.92 ms ^{-2}$