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Chemistry
Magnetic moment of Cr(Z=24), Mn +(Z=25) and Fe 2+(Z=26) are x, y, z. They are in order
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Q. Magnetic moment of ${Cr}(Z=24), Mn ^{+}(Z=25)$ and $Fe ^{2+}(Z=26)$ are $x, y, z$. They are in order
The d-and f-Block Elements
A
$x < y< z$
7%
B
$x=y< z$
7%
C
$z< x= y$
39%
D
$x=y=z$
50%
Solution:
Magnetic moment $\mu=\sqrt{N(N+2)}$ BM
Where, $N=$ unpaired electrons
${Cr}(24)[ Ar ] 3 d^5 4 s^1 \,\,\, N=6, \mu=\sqrt{48} BM =x$
$Mn ^{+} \,\,\,[ Ar ] 3 d^5 4 s^1 \,\,\, N=6, \mu=\sqrt{48} BM =y$
$Fe ^{2+} \,\,\,[ Ar ] 3 d^6 \,\,\, N=4, \mu=\sqrt{24} BM =z$
Thus, $z< x=y$