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Q.
Magnetic moment of ${ }_{25} Mn ^{x+}$ is $\sqrt{35}$ B.M. Then the value of $x$ is
Classification of Elements and Periodicity in Properties
Solution:
$25^{ Mn }-[ Ar ] 3 d ^{5} 4 s ^{2}$
Given $\sqrt{n(n+2)}=\sqrt{35}$
$\Rightarrow n=5$
Hence, to have ' $5$ ' unpaired electrons $Mn$ must be in ' $+2$ ' state.
