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Physics
Magnetic field at the centre of a circular loop of area A is B. The magnetic moment of the loop will be
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Q. Magnetic field at the centre of a circular loop of area $A$ is $B$. The magnetic moment of the loop will be
VITEEE
VITEEE 2010
A
$\frac{B A^{2}}{\mu_{0} \pi}$
12%
B
$\frac{B A^{3 / 2}}{\mu_{0} \pi}$
21%
C
$\frac{B A^{3 / 2}}{\mu_{0} \pi^{1 / 2}}$
7%
D
$\frac{2 B A^{3 / 2}}{\mu_{0} \pi^{1 / 2}}$
60%
Solution:
$B=\frac{\mu_{0}}{4 \pi} \frac{2 \pi i}{r}=\frac{\mu_{0} i}{2 r}$
or $i=\frac{2 B r}{\mu_{0}}$
Also, $A=\pi r^{2}$ or $r=\left(\frac{A}{\pi}\right)^{1 / 2}$
Magnetic moment, $M=i A=\frac{2 B r}{\mu_{0}} A$
$=\frac{2 B A}{\mu_{0}} \times\left(\frac{A}{\pi}\right)^{1 / 2}$
$=\frac{2 B A^{3 / 2}}{\mu_{0} \pi^{1 / 2}}$