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Q. Magnetic field at point 'P' of given current distribution is :-Physics Question Image

Solution:

$B _{ P }=\frac{\mu_{0} I }{4 \pi a }+\frac{\mu_{0}(2 I )}{4 \pi(2 a )} \odot$
$=\frac{\mu_{0} I }{2 \pi a } \odot$