Question

Magnetic field at point '$P$' due to given current distribution :-

• A. $\frac{\mu_{0} I }{4 \pi a } \odot$
• B. $\frac{\mu_{0} I }{2 \pi a } \odot$
• C. $\frac{\mu_{0} I}{\pi a } \otimes$
• D. Zero

Answer 1

Answer: (B)

Due to segment $1 \,\& \,3 B=0$
Due to $2 \,\&\, 4=\frac{\mu_{0} I }{4 \pi a } \odot+\frac{\mu_{0} I }{4 \pi a } \odot$
$B _{\text {net } P }=\frac{\mu_{0} I }{2 \pi a } \odot$