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Q.
$ \left[ ML^{2}T^{-3}I^{-1} \right] $ is the dimension of
AMUAMU 2003
Solution:
We know that
Potential $V=\frac{\text { energy }(Q)}{\text { charge }(q)}$
Dimensions of energy $(Q)=\left[ ML ^{2} T ^{-2}\right]$
Dimensions of charge $(q)=[ IT ]$
$\therefore $ Dimensions of potential $V=\frac{\left[ ML ^{2} T ^{-2}\right]}{[ IT ]}$
Dimension's of potential $V=\left[ ML ^{2} T ^{-3} I ^{-1}\right]$