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  4. Lowering of vapour pressure of an aqueous solution of a non-volatile non-electrolyte 1 m aqueous solution at 100°C is,

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Q. Lowering of vapour pressure of an aqueous solution of a non-volatile non-electrolyte 1 m aqueous solution at 100$^\circ$C is,

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Solution:

$p^\circ $ = 760 Torr
A 1 m aqueous solution contains 1 mol of solute in 100 g (55.5 mol) of water
$\therefore $ $x_B = \frac{1}{ 1+ 55.5} = \frac{1}{56.5}$
$\frac{\Delta_p}{p} = x_B$
$\Delta p = px_B = \frac{760 \, Torr}{56.5} $ = 13.45 Torr.