Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Lowering of vapour pressure of an aqueous solution of a non-volatile, non-electrolyte 1 molal aqueous solution at $100^{\circ} C$ is:

Solutions

Solution:

$P ^{0}=760$ torr; 1 molal aqueous solution contains 1 mole of solute in $1000 g (55.5 mol )$ of water.

$x_{B}=\frac{1}{1+55.5}=\frac{1}{56.5}$

$\frac{\Delta P}{P}=X_{B}, \Delta P=p X_{B}$

$\Rightarrow \frac{760 \times 1}{56.5}=13.45$ torr