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  4. log ( tan 18°) + log ( tan 36°) + log ( tan 54°) + log ( tan 72°) =

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Q. $\log ( \tan 18°) + \log ( \tan 36°) + \log ( \tan 54°) + \log (\tan 72°) = $

Trigonometric Functions

Solution:

$\log ( \tan 18° \tan 36° \tan 54° \tan 72°) = \log 1$
$[\because \:\:If A+ B = 90^\circ \, \Rightarrow \, \tan \, A \, \tan \, B = 1]$