1. Tardigrade
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  3. Chemistry
  4. Lithium being very small in size, polarises a large CO 32- ion leading to the formation of more stable

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Q. Lithium being very small in size, polarises a large $CO _{3}^{2-}$ ion leading to the formation of more stable

The s-Block Elements

Solution:

Lithium being very small in size, polarises a large $CO _{3}^{2-}$ ion leading to the formation of more stable $Li _{2} O$ and $CO _{2}$.