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  4. Line L, perpendicular to the line with equation y = 3x - 5, contains the point (1, 4). The x-intercept of L, is

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Q. Line $L$, perpendicular to the line with equation $y = 3x - 5$, contains the point $(1, 4)$. The x-intercept of $L,$ is

Straight Lines

Solution:

$L:(y-4)=\frac{-1}{3}(x-1)$
put $y=0, x=13$